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Write a linear factorization of the function f(x)=x^4+9x^2a) f(x)=x^2(x+3i)(x-3i)b) f(x)=x^2(x+3i)^2c) F(x)=x^2(3x+i)(3x-i)d) F(x)=x^2(3x+i)^2

User Kishorekumaru
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1 Answer

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The linear factorization of the function is f(x) = x² (x + 3i) (x - 3i) (option A)

Step-by-step explanation:

f(x)=x^4+9x^2

we factorize x² as it is common to both

f(x) = x²(x² + 9)

The next thing is to factorize (x² + 9)

To do that we need to introduce complex numbers as it is not possible to factorize sum of two squares with real numbers.

(x² + 9) = x² + 3² (sum of two squares)

the complex number: i² = -1

x² + 3² = x² +(1) 3² = x² - (-1)(3²)

x² - (-1)(3²) = x² - (i²)(3²)

recall difference of two squares:

a² - b² = (a+b) (a-b)

x² - (i²)(3²) = x² - (3i²)

= (x + 3i) (x - 3i)

(x² + 9) = (x + 3i) (x - 3i)

f(x) = x²(x² + 9) = x² (x + 3i) (x - 3i)

The linear factorization of the function is f(x) = x² (x + 3i) (x - 3i) (option A)

User Filaton
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