b = 2 and s = 4 (option C)
b = 0 and s = 8 (option E)
Step-by-step explanation:
The budget = $150
Since we can't exceed this amount, it will be represented as less than or equal to 150
≤ 150
let the number of baskeball = b
The cost of one basketball = $20
let the number of soccer balls = s
The cost per soccer balls = $18
The equation becomes:
The cost of one basketball(the number of baskeball) + The cost per soccer balls(number of soccer balls ) ≤ 150
20(b) + 18(s) ≤ 150
20b + 18s ≤ 150
From the equation, we will determine which of the options falls within it.
If after inserting the number of balls and soccer it falls below or equal to $150, then the combination can be purchased with the budget.
a) when b = 4, s = 7
20(4) + 18(7) = 206
206 > 150
b) b = 8, s = 0
20(8) + 18(0) = 160 + 0 = 160
160 > 150
c) b = 2, s = 4
20(2) + 18(4) = 40 + 72 = 112
112 < 150
Hence, combination can be purchased with the budget.
d) b = 5, s = 3
20(5) + 18(3) = 100 + 54 = 154
154 > 150
e) b = 0, s = 8
20(0) + 18(8) = 0 + 144 = 144
144 < 150
Hence, combination can be purchased with the budget.
Option C and E