Question

= 1

= 2
5
= 3
10
= 6
7
8
Write a balanced half-reaction for the reduction of gaseous oxygen (02) to liquid water
to liquid water (H2O) in acidic aqueous solution. Be sure to add physical state symbols
where appropriate.
a​

Answer 1

A balanced half-reaction :

O₂(g)+ 4H⁺(aq)+ 4e⁻⇒2H₂O(l)

Further explanation

Given

Reduction of gaseous oxygen (O₂) to liquid water(H₂O)

Required

A balanced half-reaction

Solution

Step 1 : Equalize the number of elements by adding coefficients

Equates element O

O₂(g)⇒2H₂O(l)

Step 2 : Equalize H by adding H⁺ on the opposite side (the deficient area of H).

O₂(g)+ 4H⁺(aq)⇒2H₂O(l)

Step 3 : Equalized the charge using the addition of electrons (e⁻) along the H⁺ field.

O₂(g)+ 4H⁺(aq)+ 4e⁻⇒2H₂O(l)