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A copper wire 4.727 m long has a diameter of 0.012 m. If the wire is connected to a 0.093 V battery, what is the current in the wire? The resistivity of copper is 1.7 x 10^-8 ohm m.

User Duc Nguyen
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1 Answer

14 votes
14 votes

This problem requires us to use Ohm's second law. It tells us:


R=(\rho L)/(A)

Where p is the resistivity, L is the length of the conductor and A is its area. For our problem, the resistance of the conductor will be:


R=(1.7*10^(-8)*4.727)/(((\pi *0.012^2)/(2)))=3.5526*10^(-4)\Omega

If we then apply Ohm's first law, we'll have:


I=(V)/(R)=(0.093)/(3.5526*10^(-4))=261.7766A

Then, our current will be I=261.7766A

User Dennis Gloss
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