Answer:
Yes, it is possible
Explanation:
Take a function y= f(x). When it is reflected across the x-axis the x-coordinates do not change but the y coordinates become the negative of the pre-image
In other words reflection f'(x) of f(x) over the x-axis is y = -f(x)
If we reflect f'(x) over the x-axis then the resultant reflection is
f''(x) = -f'(x) = -(-f(x)) = f(x)
So we get the original image after two consecutive reflections along the x-axis