Question

A 1100 kg car accelerates from 48.0 km/hr to 59.0 km/he 100 m. What was the magnitude of the net force acting

on the car?

Answer 1

Step-by-step explanation:

Given:

m = 1100 kg

V₁ = 48.8 km / h = 48.8*1000 m / 3600 s ≈ 13.6 m/s

V₂ = 59.0 km / h = 59.0*1000 m / 3600 s ≈ 16.4 m/s

S = 100 m

_______________

F - ?

Acceleration:

S = (V₂² - V₁²) / (2*a)

a =(V₂² - V₁²) / (2*S) = (16.4² - 13.6²) / (2·100) ≈ 0.42 m/s²

Force:

F = m*a = 1100 * 0.42 = 462 N