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Given the perimeter of a rectangle is 96 meter and the length is twice the width, find the dimensions. Solve algebraically.
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Given the perimeter of a rectangle is 96 meter and the length is twice the width, find the dimensions. Solve algebraically.

User Floatingmuseum
by
6.2k points

2 Answers

4 votes
96/6=16

16+32+16+32=96

The length would be 32 while the width would be 16.
User Cscan
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5.7k points
1 vote
96 + 96
2(96x2) is the answer
User Johannes Titz
by
5.8k points
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