Question

If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79.63 g 194.3 g

Answer 1

Answer:79.63g

Step-by-step explanation:

Edg2021

Answer 2

1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu

2) we need to convert the grams of CuSO₄ to moles using the molar mass.

molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol


`200.0 g CuSO_4 ( (1 mol)/(160 grams) )= 1.25 mol CuSO_4`

3) convert moles of CuSO₄ to moles of Cu


`1.25 mol CuSO_4 ( (1 mol Cu)/(1 mol CuSO_4) )= 1.25 mol Cu`

4) convert moles of Cu to grams using it's molar mass.

molar mass Cu= 63.5 g/mol


`1.25 mol ((63.5 grams)/(1 mol) )= 79.4 grams Cu`

I did it step-by-step as the explanation but you can do all of this in one step.


`200.0 g CuSO_4 ( (1 mol CuSO_4)/(160 g) ) ( (1 mol Cu)/(1 mol CuSO_4) ) ( (63.5 grams)/(1 mol Cu) )= 79.4 grams Cu`