Question

An apple falls out of a tree and takes 1.75 seconds to strike the ground.what was the velocity of the apple when it hit the ground

Answer 1

assuming acceleration is 10
let the final velocity be x
(x-0) /1.75= 10 where 0 is initial velocity at its highest point
x= 17.5m/s

Answer 2

`v_f=17.15(m)/(s)`

Step-by-step explanation:

The apple is in free fall, therefore we can use the kinematic equations, especifically the which one that relate final speed to acceleration of gravity and time:

`g=(v_f-v_o)/(t)`

The initial speed is zero, since falls out of the tree and recall that
`g=9.8(m)/(s^2)`. So, Rewriting for final speed:

`v_f=gt\\v_f=(9.8(m)/(s^2))(1.75s)\\v_f=17.15(m)/(s)`