Question

The initial temperature of a bomb calorimeter is 28.50°

c. when a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°
c. if the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 j/(gi°
c., how much heat is absorbed by the reaction?

Answer 1

The answer is 5,170 J

Answer 2

The answer is 5174400 J.

Step-by-step explanation:

Here you have to keep in mind the equation to determine the amount of heat (Q) that one body of mass m can take. The equation is : [tex] Q=mc\Delta T [\tex]

where m is the mass, c is the specific heat and [tex] \Delta T [\tex] the temperature variation. This way: Q=1400kg*3.52J/gºC*(28.5-27.45) ºC=1400000 g*3.52 J/gºC * (28.5-27.45)ºC=5174400J=5174.4 kJ=5.17 MJ.