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Simplify 13 over the quantity of negative 3 plus 2i.

User Kortschot
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2 Answers

6 votes

Answer:

A= -3-2i

Explanation:

User Pusparaj
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A complex number in the denominator is eliminated by multiplying the fraction by 1 in the form of the conjugate of that denominator divided by itself.


(13)/(-3+2i)=(13)/(-3+2i)\cdot (-3-2i)/(-3-2i)=(13(-3-2i))/((-3+2i)(-3-2i))\\\\=(13(-3-2i))/((-3)^2-(2i)^2)=(13(-3-2i))/(9+4)\\\\=-3-2i

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A graphing or scientific calculator that handles complex numbers can do this simplification for you.

Simplify 13 over the quantity of negative 3 plus 2i.-example-1
User Yan Foto
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