Question

Use point-slope form to write the equation of a line that passes through the point (8,−5) with slope -20/11 .

Answer 1

`(\stackrel{x_1}{8}~,~\stackrel{y_1}{-5})\qquad \qquad \stackrel{slope}{m}\implies - \cfrac{20}{11} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{-\cfrac{20}{11}}(x-\stackrel{x_1}{8})\implies y+5=-\cfrac{20}{11}x+\cfrac{160}{11} \\\\\\ y=-\cfrac{20}{11}x+\cfrac{160}{11}-5\implies y=-\cfrac{20}{11}x+\cfrac{105}{11}`