Question

How would I solve this? I’m not very good at conversions

Answer 1

From the question;

A technical mechinist is asked to build a cubical steel tank that will hold 220L of water

this implies

`\text{Volume of water = 220L}`

Using the formula of volume of cube

`\text{volume of cube = l}^3`

converting Liters to cubic meter

WE have

`220\text{ L = }0.22m^3`

Hence

`Volumeofcubical-\tan k=0.22m^3`

Finding the length

`\begin{gathered} l^3=0.22m^3 \\ l=\sqrt[3]{0.22m^3^{}} \\ l=0.604m \end{gathered}`

Hence the smallest possible inside length of the cubical tank is 0.604m