Question

Select the exclusion that fits best with this problem.4x² - 4x + 1/8x ^3-1

Answer 1

2x - 1 = 0, 4x^2 + 2x + 1 = 0

Explanation:

Option A is correct on Odyssey

Answer 2

The answer is A.

EXPLANATION :

From the problem, we have :

`(4x^2-4x+1)/(8x^3-1)`

The exclusion is when the denominator is equal to 0.

So equate the denominator to 0.

`8x^3-1=0`

Factor completely using the difference of two cubes :

`a^3-b^3=(a-b)(a^2+ab+b^2)`

So that will be :

`\begin{gathered} 8x^3-1=0 \\ (2x-1)(4x^2+2x+1)=0 \\ \text{ Equate both factors to 0} \\ 2x-1=0 \\ and \\ 4x^2+2x+1=0 \end{gathered}`