ax^2+bx+c
a=1
b=-6
c=-16
Complete the square:
a ( x+ d)^2+e=0
Where:
d= b/2a = -6/ (2x1) = -3
e= c-b^2/4a = -16 -[ (-6)^2/4(1)] = -25
1 (x-3)^2-25 = 0
(x-3)^2 = 25
Take the square root on both sides of the equation:
x-3 = 5
Add 3 to both sides:
x =8
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