Question

The equation 2sin x+sqrt3 cot x=sin x is partially solved below

Answer 1

Trigonometric Equations Practice:

1. (A): cos^2 (x) - sqrt(3)*cos(x) - 1 = 0

2. (B): f(x) = sqrt(sin x)

3. (D): 7.6 hours

Trigonometric Equations:

1. (C): three

2. (B): The equation was factored incorrectly.

3. (A & E) sec x= -1 & sec x=3/2

4. (B): sqrt2/2

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Answer 2

Given:

`2sinx+√(3)cotx=sinx`

The partially solved equation is,

`sin^2x+√(3)cosx=0`

To find: The final step

Step-by-step explanation:

We know that,

The trigonometric identity is,

`1-cos^2x=s\imaginaryI n^2x`

Using this we get,

`1-cos^2x+√(3)cosx=0`

Multiplying by -1 on both sides, we get

`cos^2x-√(3)\cos x-1=0`

Final answer:

`cos^2x-√(3)\cos x-1=0`