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33 votes
33 votes
Evaluate the function at the given value of the variable. f(×) = I will attach image

1 Answer

20 votes
20 votes

\begin{gathered} f(x)=2x^2+3x+1 \\ f(5)=2*(5*5)+3*5+1 \\ f(5)=50+15+1 \\ f(5)=66 \\ f(-6)=2*(-6*-6)+3*(-6)+1 \\ f(-6)=72-18+1 \\ f(-6)=55 \end{gathered}

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