Question

Which of the following describes sec(205°)?

sec⁡(205°) < -1
sec⁡(205°) ≥ -1
sec⁡(205°) > 1
sec⁡(205°) = 1

Answer 1

(A)
`sec(205^(\circ))<-1`

Step by step explanation:

The given equation is:

`sec(205^(\circ))`

which can be written as:

`sec(205^(\circ))=(1)/(cos(205^(\circ)))`

Substituting the value of
`cos(205^(\circ))` in the above equation , we get

`sec(205^(\circ))=(1)/(-0.906)`

`sec(205^(\circ))=(-1)/(0.906)`

`sec(205^(\circ))=-1.103`

Therefore,
`sec(205^(\circ))<-1`

Hence, option A is correct.

Answer 2

This is the concept of trigonometry, to solve the question we proceed as follows;
sec(x)=1/cosx
thus;
sec(205)=1/cos205
=1/-0.9063
=-1.1034
this implies that:
sec(205)<-1