Question

Given f (x), find g(x) and h(x) such that f(x)= g(h(x)) and neither g(x) nor h(x) is solely x.
`\sqrt[3]{3x ^(3) - 1 } - 3`answer: g(x) =h(x) =

Answer 1

Problem

Solution

For this case we can use this functions:

h(x) = 3x^3 -1

g(x)= x^(1/3) -3

And we satisfy the condition that

f(x) = g(h(x))