Question

Roy pushes a box of mass 16.6 kilograms across a floor by exerting a horizontal force of 99.1 newtons. The coefficient of kinetic friction between the box and the floor is 0.324, and Roy pushes the box 11.4 meters. What work does Roy do? Include units in your answer. Answer must in 3 significant digits.l

Answer 1

Given,

The mass of the box, m=16.6 kg

The force exerted by Roy, F=99.1 N

The coefficient of friction between the floor and the box, μ=0.324

The distance for which Roy pushes the box, d=11.4 m

The work done is given by the product of the force exerted by a source and the distance for which the force was exerted.

Thus the work done by Roy is given by,

`W=F* d`

On substituting the known values,

`\begin{gathered} W=99.1*11.4 \\ =1129.74\text{ J} \\ \approx1130\text{ J} \end{gathered}`

Thus the work done by Roy is 1130 J