Question

When 4 moles of aluminum are allowed to react with an excess of chlorine gas, Cl2, how many moles of aluminum chloride are produced?

Answer 1

2Al+3Cl2==>2AlCl3
(4mol Al)(2 mol AlCl3/2 mol Al)=4 mole AlCl3

Answer 2

Answer: 4 moles of aluminium chloride will be produced in the following reaction.

Step-by-step explanation:

The balanced chemical equation for the formation of aluminium chloride is:

`2Al(s)+Cl_2(g)\rightarrow 2AlCl_3(s)`

It is given that chlorine gas is present in excess, therefore it is considered as an excess reagent and aluminium is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

2 moles of aluminium produces 2 moles of aluminium chloride.

So, 4 moles of aluminium will produce =
`(2)/(2)* 4=4` moles of aluminium chloride.

Hence, 4 moles of aluminium chloride will be produced in the given reaction.