Question

What are th minimum,first quartile,median,third quartile,and maximum of the data set? 63,98,40,32,20,80,102,65

Answer 1

Median: 64
Minimum: 20
Maximum: 102
First Q: 32
Third Q: 98

Answer 2

First quartile = 36 , Median = 64 , Minimum = 20 ,

Maximum = 102, Third quartile = 89.

Explanation:

Given : 63,98,40,32,20,80,102,65.

To find : What are the minimum,first quartile,median,third quartile,and maximum of the data set.

Solution : We have given that 63,98,40,32,20,80,102,65.

Arranging in ascending order

20 , 32 , 40 ,63 ,65 ,80 ,98 , 102.

Median =
`(63 +65)/(2)  =(128)/(2)` = 64.

Minimum = 20 .

Maximum = 102.

First quartile = [tex]\frac{32 +40}{2} = 36.

Third quartile = [tex]\frac{80 +98}{2} = 89.

Therefore, First quartile = 36 , Median = 64 , Minimum = 20 ,

Maximum = 102, Third quartile = 89.