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Evaluate a³-5g+(34-30)^0.5*(g+1)^0.5/2 if a=2 and g = 3

User Stan Bondi
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1 Answer

18 votes
18 votes

We are given the following expression


a^(3)-5g+\sqrt[]{34-30}+\frac{\sqrt[]{g+1}}{2}

whenever a=2 and g=3. What we should do, is replace the values of a and g and then operate accordingly. We will do this expression by expression and then operate eache term.

Consider the term a³. If a=2, then


a^(3)=2^(3)=8

in the case for 5g, if g=3, then


5\cdot g=5\cdot3=15

Now, let us analize sqrt(g+1), if g=3, then g+1=4. Then


\frac{\sqrt[]{g+1}}{2}=\frac{\sqrt[]{4}}{2}

in this case, we will always use positive square roots, so


\frac{\sqrt[]{g+1}}{2}=\frac{\sqrt[]{4}}{2}=(2)/(2)=1

Finally, we will calculate the remaining term


\sqrt[]{34-30}=\sqrt[]{4}=2

Then, the final procedure would be


8-15+2+1\text{ = 11-15 =-4}

So the final answer is -4

User Ttmt
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