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Stot asked Mar 18, 2023

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Stot asked Mar 18, 2023

by Stot

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10 votes

For the reaction:

$Br_2+Cl_2\rightarrow2BrCl$

The equilibrium constant expression is:

$K_{}=(\lbrack BrCl\rbrack^2)/(\lbrack Br_2\rbrack\lbrack Cl_2\rbrack)$

Telexx answered Mar 22, 2023

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