Question

What is the molarity of a solution with 18.10 grams of solute and a volume of 1890.0 mL? The solute has a molar mass of 237.8 g/mol.

Answer 1

1) Molarity equation

`M=\frac{\text{number of moles}}{\text{liters of solution}}`

M= Molarity

2) Converting grams (g) into moles (mol)

`\text{moles}=18.10g\cdot\frac{1\text{ mol}}{237.8g}=0.07611\text{ mol}`

3) Converting mL into L

`L=1890.0mL\cdot(1L)/(1000mL)=1.890L`

4) Plug in quantities

`M=(0.07611mol)/(1.89L)=0.04027M`

The molarity of the solution is 0.04027M.