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Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper. What is the probability of selecting an odd number followed
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Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper.

What is the probability of selecting an odd number followed by an even number?

A. 1/4
B. 1/5
C. 5/18
D. 2/9

User Silvio Biasiol
by
8.0k points

2 Answers

3 votes
5/10 * 5/9
1/2 * 5/9
5/18
User Chunpoon
by
8.0k points
0 votes
Note: Since the question states that the first number is not replaced, the second number is "dependent" on the first.

Problem Solved:

Probability (odd, then even) = (5/10) x (5/9)
(5/10) x (5/9)
= 25/90
= 5/18 (simplified)

Answer: C. 5/18

User Ivan Pirog
by
8.3k points
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