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Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 3 over 2x + 5.

y = negative 2 over 3x
y = negative 2 over 3x − 7
y = 3 over 2x
y = 3 over 2x + 7

User Dubbe
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2 Answers

6 votes
you the point - slope form of the equation of a straight line

y - y1 = m(x - x1)

m = slope = 3/2 and x1 = 2 , y1 = 3 so we have

y - 3 = (3/2)(x - 2)

y - 3 = (3/2)x - 3

y = (3/2)x


Choice C is correct
User Jithinroy
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0 votes

Answer:


Y=(3)/(2)x

Explanation:

In order to solve this problem we just have to know the formula of the equation of a line, this is in the form of the slope:


y=(3)/(2x+5)

The formula of the line on its slope form is:

y=mx+c

m is the slope, in our previous line the slope would be:
(3)/(2)

Since they are parallel lines, they have the same slope, so our line would be:


y=(3)/(2)x

And we can confirm it by inserting the values of the point that we know:


y=(3)/(2)x


3=(3)/(2)2


3=3

We know that it is correct.

User Juanillo
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