Question

Does anybody know how to solve a problem like this (6x^5)^-3? I don't know where to begin.

Answer 1

remember

`(x^m)^n=x^(mn)`
and

`(ab)^c=(a^c)(b^c)`
and

`x^(-m)= (1)/(x^m)`

so



`(6x^5)^(-3)=(6^(-3))((x^5)^(-3))=`

`( (1)/(6^5) )(x^(-15))=( (1)/(7776) )( (1)/(x^(15)))=( (1)/(7776x^(15)))`