Question

you are asked to draw a colored marble out of the box they are 9 red marbles 3 blue marbles and 4 Green marbles in the Box what is the probability of drawing a blue marble and then a green marble with replacement round to three decimal places

Answer 1

THe probability is 0.047.

Given:

Number of red marbles is, n(R) = 9.

Number of blue marbles is, n(B) = 3.

Number of green marbles is, n(G) = 4.

The objective is to daw a blue marble and then a green marble with replacement.

The total number of marbles is,

`\begin{gathered} N=n(R)+n(B)+n(G) \\ N=9+3+4 \\ N=16 \end{gathered}`

Now, the probability of drawing a blue marble and then a green marble with replacement will be,

`\begin{gathered} P(B\cap G)=P(B)\cdot P(G) \\ =(n(B))/(N)\cdot(n(G))/(N) \\ =(3)/(16)\cdot(4)/(16) \\ =0.047 \end{gathered}`

Hence, the required probability is 0.047.