Question

In a certain normal distribution of scores, the mean is 50 and the standard deviation is 6. Find the z-score corresponding to a score of 60.

Answer 1

z-score = 1.667

Explanation:

The provided information are:

Population mean
`(\mu)` = 50

Population standard deviation
`(\sigma)` = 6

Score (X) = 60

The formula to calculate the z-score is:

`z=(X-\mu)/(\sigma)`

The z- score can be calculated as:

`z=(X-\mu)/(\sigma)\\z=(60-50)/(6) \\z= 1.667`

Hence, the z-score is 1.667.