Question

N a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds?

R=round
r = wrinkled
         Y = yellow
         y = green

Answer 1

The question is asking to choose among the following question that states the probability of having green and wrinkled seeds and base on the given data, I would say that the ratio would be 1:16. hope this helped out!!!!

Answer 2

1/16

Step-by-step explanation:

See the Punnett square diagram to observe the result of the cross between the round and yellow plants (RrYy X RrYy).

Since round (R) is dominant over wrinkled (r) and yellow (Y) is dominant over y (green), the plant with genotype rryy would have wrinkled and green phenotype as these are recessive characters.

From the given cross in the Punnett square, we can observe that there is a total of 16 possible progenies and out of these only 1 has the wrinkled and green phenotype.

Therefore the probability is 1/16.