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Suppose that a guitar company estimates that its monthly cost isC(x) = 400x² + 600x and its monthly revenue isR(x) = -0.4 +600x²200x +500, where x is in thousands ofguitars sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?O A. P(x) = -0.4x³ + 200x² - 800x + 500B. P(x) = 0.4x³ - 200x² +800x - 500c. P(x) = 0.4x³ + 200x² 800x + 500D. P(x) = -0.4x³ + 1000x² + 400x + 500

User Stav
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1 Answer

21 votes
21 votes

Given:

C(x) = 400x² + 600x and its monthly revenue is

R(x) = -0.4 +600x²200x +500,

Required:

To tell which option is correct

Step-by-step explanation:

According to the question

p(x)=R(x)-C(x)


User Mrganser
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