Question

A

given amount of gas occupies 10.0dm3 at 4
Atm and 273°c. The number of moles of the gas
present is(molar volume of a gas at s.t.p=22.4dm3)

Answer 1

To solve this question, we need to use the following formula: PV = nRT

where:

P = pressure

V = voume

n = number of moler

R = gas constant

T = temperature

The question gives us the following values:

P = 4 atm

V = 10 dm³

n = we will find out

R = 0.082 atm.L/K.mol

T = 273 °C

- We need to transform all units to the same constant R has. So we need to transform dm³ into liters and 273 °C into kelvin.

1 dm³ --- 1 L

10 dm³ --- 10 L

TK = 273 + 273 = 546K

- Now, we replace the values in the formula:

4 x 10 = n x 0.082 x 546

n = 40/44.772

n = 0.89 moles

Answer: 0.89 moles of the gas