Question

A gas that exerts a pressure of ____ psi in a container with a volume of 12.45 L will exert a pressure of 1112 psi when transferred to a container with a volume of 6.531 L. (Solve the ____)

Answer 1

Here, we may apply Boyle's law, which is mathematically expressed as:
PV = constant
So, we equate the product of the the initial pressure and volume to the product of the final pressure and volume as such:
P * 12.45 = 1112 * 6.53
P = (1112 * 6.53) / 12.45
P = 583.2 PSI

Answer 2

A gas that exerts a pressure of 583.33 psi. psi in a container with a volume of 12.45 L will exert a pressure of 1112 psi when transferred to a container with a volume of 6.531 L.

Step-by-step explanation:

Initial pressure exerted by the gas =
`P_1`

Initial volume occupied by the gas =
`V_1=12.45 L`

Final pressure exerted by the gas =
`P_2=1112 psi`

Final volume of the gas occupied by the gas =
`V_2=6.531 L`

Applying Boyle's law:

`P_1* V_1=P_2* V_2`

`P_1=(P_2* V_2)/(V_1)=(1112 psi* 6.531 L)/(12.45 L)=583.33 psi`

The initial pressure exerted by the gas was 583.33 psi.

A gas that exerts a pressure of 583.33 psi. psi in a container with a volume of 12.45 L will exert a pressure of 1112 psi when transferred to a container with a volume of 6.531 L.