Question

Each letter of the alphabet is printed on an index card. What is the theoretical probability of randomly choosing any letter except Z? Write your answer as a fraction or percent rounded to the nearest tenth.

The theoretical probability of choosing a letter other than Z is __.

Answer 1

The theoretical probability of randomly choosing any letter except Z from the alphabet (represented on index cards) is 25/26, or approximately 96.2% when rounded to the nearest tenth.

Step-by-step explanation:

The theoretical probability of choosing any letter except Z from a set of index cards each having one letter of the English alphabet on it is calculated by contrasting the number of favorable outcomes with the total number of possible outcomes. Since there are 26 letters in the alphabet and only one letter Z, the number of favorable outcomes (choosing a letter that is not Z) is 25. Hence, the probability will be the number of favorable outcomes over the number of possible outcomes:

Probability = Favorable outcomes / Total outcomes = 25 / 26.

To express this as a percentage rounded to the nearest tenth, we convert the fraction to decimal and then multiply by 100%:

Percentage ≈ (25/26) × 100% ≈ 96.2%.

Answer 2

The theoretical probability of choosing a letter other than Z is 96.2%

Step-by-step explanation:

We know that there are 26 alphabets.

Also, the number of alphabets which are other than Z are: 25

Now we are asked to find the theoretical probability of randomly choosing any letter except Z :

It is the ratio of the number of alphabets other than Z to the total number of alphabets.

which is calculated as:

`Theoretical\ Probability=(25)/(26)\\\\\\Theoretical\ Probability=0.961538`

In percent to the nearest tenth the theoretical probability is given by:

96.2%