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9 votes
9 votes
Find the equation of the circle in standard form for the given center (h, k) and radiusr: (h, k) = (0, 0), r = 44x2 + 4y2 = 16x2 + y2 = 4x2 + y2 = 162x2 + 2y2 = 16

User Guerline
by
3.2k points

1 Answer

24 votes
24 votes

Hello!

First, let's write some important information:

Center = (0, 0), r = 4.

To write the equation of the circle, we must use the formula below:


\left(x-x_C\right)^2+(y-y_C)^2=r^2

As we know the values of the center and the radius, let's replace them in the equation:


\begin{gathered} \left(x-0\right)^2+(y-0)^2=4^2 \\ \\ \boxed{x^2+y^2=16} \end{gathered}

Answer:

Alternative C.

User Vivek Kumar Ray
by
3.0k points
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