Question

If the function f(x) = log2x what is the value of 2^2y=6?

0.47
4.01
2.58
1.29

Answer 1

`\bf 2^(2y)=6\implies log(2^(2y))=log(6)\implies 2ylog(2)=log(6) \\\\\\ 2y=\cfrac{log(6)}{log(2)}\implies y=\cfrac{(log(6))/(log(2))}{2}`