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Given f(x)=17-x^2, what is the average rate of change in f(x) over the interval [1, 5]?

A: -6
B: -1/2
C: 1/4
D: 1

User Victorsc
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\bf slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby \begin{array}{llll} average\ rate\\ of\ change \end{array}\\\\ -----------------------------\\\\ f(x)=17-x^2\quad \begin{cases} x_1=1\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(1)}{5-1} \\\\\\ \cfrac{(17-5^2)-(17-1^2)}{5-1}\implies \cfrac{-8-16}{4}\implies \cfrac{-24}{4}\implies -6
User Jachin
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