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Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, what is the greatest number of rides Daniel can go on?

User Heading
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2 Answers

6 votes
The greatest number of rides he can go = ($25-$4)/$1,50=14
User IgNite
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5 votes
25= 1.50x+4
Subtract 4
21= 1.50x
Divide by 1.50
X=14 rides or less
User Carson
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