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Log 3(x^2+6x)=log(2x+12)
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Log 3(x^2+6x)=log(2x+12)

User HoosierDaddy
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log 3(x²+6x)=log(2x+12). I assume that 3 is a factor of a log with base 10:

if so, then:
log(3x²+18x)=log(2x+12)

==> 3x²+18x=2x+12==> 3x²+16x-12 = 0
solve this quadratic equation & you will find: x'=2/3 & x"=-6

User Davoud
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