Question

I do not know how to solve this problem or know what to do with the exponents

Answer 1

k, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also

`(ab)^c=(a^c)(b^c)`
and

`x^(-m)= (1)/(x^m)`
and

`x^ (m)/(n)= \sqrt[n]{x^m}`
and

`( (x)/(y) )^m= (x^m)/(y^m)`
and

`(x^m)^n=x^(mn)`
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)


so

`( (-7x^ (3)/(2) )/(5y^4) )^(-2)`=

`( (-7)/(5) )^(-2)( (x^ (3)/(2) )/(y^4) )^(-2)`=

`( ((-7)^(-2))/(5^(-2)) )( ((x^ (3)/(2))^(-2) )/((y^4)^(-2)) )`=

`( ( (1)/((-7)^2) )/( (1)/(5^2) ) )( (x^ (-6)/(2) )/(y^(-8)) )`=

`( ( (1)/(49) )/( (1)/(25) ) )( ((x^(-3)) )/((1)/(y^8)) )`

`( ( (1)/(49) )/( (1)/(25) ) )( ((1)/(x^3) )/((1)/(y^8)) )`=

`((25)/(49) )( (y^8)/(x^3)`=

`(25y^8)/(49x^3)`