Question

If a volume of nitrogen gas at 452 K decreases from 100.0 mL to 50.0 mL, what is the final Kelvin temperature? Assume pressure remains constant.

Answer 1

100.0mL and 50.0mL to L

452K * (.05L/.10L) = 226 K

Answer 2

Answer : The final temperature of gas will be, 226 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T`

or,

`(V_1)/(V_2)=(T_1)/(T_2)`

where,

`V_1` = initial volume of gas = 100 ml

`V_2` = final volume of gas = 50 ml

`T_1` = initial temperature of gas = 452 K

`T_2` = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

`(100ml)/(50ml)=(452K)/(T_2)`

`T_2=226K`

Therefore, the final temperature of gas will be, 226 K