Question

The sum of three consecutive odd integers is 333.Find 3 integers

Answer 1

A seed for odd numbers is:

`(2n+1)`

This means that if you change n for any number you like, you'll always get an odd number.

Now, odd numbers are 2 places away from each other. This way, the seeds for three consecutive odd numbers will be:

`\begin{gathered} (2n+1) \\ (2n+3) \\ (2n+5) \end{gathered}`

Now, this numbers add up to 333. Therefore,

`(2n+1)+(2n+3)+(2n+5)=333`

Solving for n,