Question

What is the correct simplification of the expression a to the 6th power times b to the 3rd power all over a to the 4th power times b to the second power?

Answer 1

`(a^(6) b^(3))/(a^(4) b^(2)) = a^(2)b`

The powers cancel each other out. For example (a.a.a.a.a.a)/(a.a.a.a) = a.a