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For ΔABC, ∠A = 3x - 8, ∠B = 5x - 6, and ∠C = 4x + 2. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A' = 2x + 8, ∠B' = 90 - x, and ∠C' = 5x - 14, which confirms that ΔABC∼ΔA'B'C
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For ΔABC, ∠A = 3x - 8, ∠B = 5x - 6, and ∠C = 4x + 2. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A' = 2x + 8, ∠B' = 90 - x, and ∠C' = 5x - 14, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

User SpacePotatoes
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C) ∠B = ∠B' = 33° and ∠C = ∠C' = 80°

a triangle has a total of 180 degrees.
In order to get x:
180 = 4x + 7 + 2x + 3 + 6x -10
180 = 12x - 0
x = 15

∠A = 4x + 7 = 67
∠B = 2x + 3 = 33
∠C = 6x - 10 = 80
User Ashraf Patel
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