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Which function has the greater average rate over the interval [0,3]?
f(x) = 2 √(x + 1) - 3x | g(x)---------0 | -21 | -82 | -143 | -20option 1: h(x)option 2: f(x)option 3: g(x)

Which function has the greater average rate over the interval [0,3]?f(x) = 2 √(x + 1) - 3x-example-1
User Guywithmazda
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1 Answer

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24 votes

Solution

For this case we can do the following:


f(x)=2\sqrt[]{x+1}-3

We can find:

f(0)= -1 , f(3) = 1

And we have:


\text{change}=(1+1)/(3-0)=(2)/(3)\text{ }

For the new function g(x) we have:


\text{change}=\frac{g(3)-g(0)_{}_{}}{3-0}=(-20+2)/(3-0)=-6

And for h(x) we have:


\text{change}=(h(3)-h(0))/(3-0)=(-3-0)/(3-0)=-1

For this case we can conclude that the greater rate of change needs to be g(x) no matter if is negative since we need to analyze the absolute value

User Fishbone
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