Question

Multiply (6z 2 - 4z + 1)(8 - 3z).

18z3 - 60z2 + 35z - 8
48z2 - 18z + 8
6z2 - 7z + 9
-18z3 + 60z2 - 35z + 8

Answer 1

(6z² - 4z + 1)(8 - 3z) Expand
= 48z² -18z³ - 32z +12z² +8 - 3z Collect like terms
= -18z³ + 60z² - 35z + 8

(6z² - 4z + 1)(8 - 3z) = -18z³ + 60z² - 35z + 8

Answer 2

Option (d) is correct.

The product of terms
`6z^2-4z+1` and
`8-3z` is

`-18z^3+60z^2-35z+8`

Explanation:

Given two terms
`6z^2-4z+1` and
`8-3z`

We have to find the product of the two given terms that is
`(6z^2-4z+1)(8-3z)`

Consider
`(6z^2-4z+1)(8-3z)`

`(6z^2-4z+1)(8-3z)` is same as
`(8-3z)(6z^2-4z+1)`

To find the product we first multiply each term of first bracket with each term of second one, we get,

`(8-3z)(6z^2-4z+1)=8(6z^2-4z+1)-3z(6z^2-4z+1)`

Multiply , we get,

`8(6z^2-4z+1)-3z(6z^2-4z+1)=48z^2-32z+8-18z^3+12z^2-3z`

Simplify by clubbing together like terms, we get,

`48z^2-32z+8-18z^3+12z^2-3z=-18z^3+60z^2-35z+8`

Thus, the product of terms
`6z^2-4z+1` and
`8-3z` is
`-18z^3+60z^2-35z+8`

Option (d) is correct.