Question

3x-2 over x²-2x-3 minus 1 over x-3 a. Rewrite the expression so that the first denominator is in factored form. b. Determine the LCD. (Write it in factored form.) c. Rewrite the expression so that both fractions are written with the LCD. d. Subtract and simplify.

Answer 1

`\bf \cfrac{3x-2}{x^2-2x-3}-\cfrac{1}{x-3}\qquad \qquad \begin{array}{lcclll} x^2&-2x&-3\\ &\uparrow &\uparrow \\ &-3+1&-3\cdot 1 \end{array}\qquad thus \\\\\\ \cfrac{3x-2}{(x-3)(x+1)}-\cfrac{1}{x-3}\impliedby \begin{array}{llll} \textit{LCD will then be}\\ (x-3)(x+1)\\ \textit{since it contains x-3}\\ already \end{array} \\\\\\ \cfrac{(3x-2)-(x+1)1}{(x-3)(x+1)}\implies \cfrac{3x-2-x-1}{(x-3)(x+1)} \\\\\\ \cfrac{2x-3}{(x-3)(x+1)}`

Answer 2

Answer: C

Step-by-step explanation im that guy