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What is the area of the composite figure if AB ≅ BC ≅ CD ≅ DA ≅ DN?

(2π + 28) mm2
(2π + 32) mm2
(2π + 40) mm2
(2π + 48) mm2

What is the area of the composite figure if AB ≅ BC ≅ CD ≅ DA ≅ DN? (2π + 28) mm2 (2π + 32) mm-example-1
User Fefe
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2 Answers

5 votes

Answer:

C

Explanation:

edge

User Carlol
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5.9k points
2 votes
Lets break this down into recognizable shapes (see the figure below). We see we have a semicircle, one square, and a trapezoid. We can find the area of each, then add them all together.

Area of a circle = pi*r^2
pi*2^2
=4pi
We have to remember that this is a semicircle, so we'll divide by two to get 2pi.

Area of a square = s^2
In this case, s=4, so 4^2 = 16

Area of a trapezoid = 1/2(b1+b2)h, where b1 and b2 are bases.
1/2(8+4)(4) = 24

24+16+2pi = (2pi+40) mm^2

:)
What is the area of the composite figure if AB ≅ BC ≅ CD ≅ DA ≅ DN? (2π + 28) mm2 (2π + 32) mm-example-1
User Icguy
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