Question

How do you solve 2x-3y=3

Answer 1

you cannot combine any the terms because x and y are two different variables. that is the most simplified you can get.

Answer 2

Answer: x = 3/2, y = 0


Equation:

2x - 3y = 3

(add 3y to both sides)

2x - 3y + 3y = 3 + 3y = 2x = 3 + 3y

(divide by 2 on both sides to isolate x)

2x / 2 = (3 + 3y) / 2

x = (3 + 3y) / 2

x = 3/2y + 3/2

then, for y, plug in equation for x value to original:

2x - 3y = 3 -------> 2(3/2y + 3/2) - 3y = 3

solve for y:

(distribute the 2 outside of parenthesis)

2(3/2y + 3/2) - 3y = 3

(reduce/simplify fractions)

6/2y + 6/2 - 3y = 3

3y + 3 - 3y = 3

0 + 3 = 3

3 = 3

so y = 0

place value for y into x equation to figure x value.

x = 3/2y + 3/2

x = 3/2(0) + 3/2

x= 0 + 3/2

x=3/2

Check (place x & y values into original equation):

2x - 3y = 3

2(3/2) - 3(0) = 3

6/2 - 0 = 3

3 = 3